Math, asked by kajal1902, 11 months ago

prove that (sin A+secA)^2 + (cosA+cosecA)^2=(1+secA.cosecA)

please answer

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Answered by Anonymous

REFER THE ATTACHMENT.

Attachments:

kajal1902: hlo dear there is (1+sec A.cosecA ) in book

Anonymous: But there should be square. Are you sure..?

Anonymous: Is it a NCERT question..?

kajal1902: no it is not ncert question

Anonymous: Then from which book..? .

kajal1902: Mathematics exam booster

Anonymous: But there should be square according to Me.

kajal1902: ohkkk dear

Answered by raga2003

LHS:- (sinA + secA)2 +( cosA + CosecA)2

= sin2A +sec2A +2sinAsecA +cos2A +cosec2A +2cosAcosecA

= (sin2A + cos2A) + (sec2A +cosec2A) +( 2sinA/cosA + 2cosA/sinA)

=1 + (1/cos2A + 1/sin2A) + ( 2sin2A +2cos2A/sinAcosA)

=1 +(sin2A +cos2A/sin2Acos2A) +[ 2(sin2A+cos2A) / sinAcosA]

=1 + 1/sin2Acos2A + 2/sinAcosA

= (1 + 1/sinAcosA)2

= (1 + cosecAsecA)2

=RHS

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prove that (sin A+secA)^2 + (cosA+cosecA)^2=(1+secA.cosecA)please answer

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prove that (sin A+secA)^2 + (cosA+cosecA)^2=(1+secA.cosecA)

please answer