Question

prove that ( sinΘ + cosΘ )^2 - ( sinΘ - cosΘ )^2 = 2sin2Θ

Answer 1

Answer:

I don't know what are you asking why are you asking and when you are asking

Step-by-step explanation:

writing you are a good child you can give this answer why were not given the answer

Answer 2

Step-by-step explanation:

(sin+cos)^2-(sin-cos)^2

sin^2+cos^2+2sincos-(sin^2+cos^2-2sincos)

sin^2+cos^2+2sincos-sin^2-cos^2+2sincos

4sincos

you said wrong

ithink you know and ask question great