Math, asked by pradeepkakarla118, 6 hours ago

Prove that sin o sin (60-0), sin (60 to)=1/4sim3o, hence
the value of sin 20. sin 40. sin80​

Answers

Answered by rajeswaribr
1

Answer:

Step-by-step explanation:

Attachments:
Answered by sayanmondal47459
0

Answer:

sin20 sin40 sin60 sin80

We know that

sinA sin(60−A) sin(60+A)=41sin3A

∴sin60×sin20  sin(60−20)sin(60+20)

=23×sin(20×3)×41

=23×sin60×41

=41×23×23

=163

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