Prove that sin o sin (60-0), sin (60 to)=1/4sim3o, hence
the value of sin 20. sin 40. sin80
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sin20 sin40 sin60 sin80
We know that
sinA sin(60−A) sin(60+A)=41sin3A
∴sin60×sin20 sin(60−20)sin(60+20)
=23×sin(20×3)×41
=23×sin60×41
=41×23×23
=163
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