Prove that
sin∅+sin2∅/1+cos∅+sin2∅=tan∅
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(sinA+sin2A)/(1+cosA+cos2A)
= (sinA+2sinAcosA)/(1+cosA+2cos^2(A)-1)
= sinA(1+2cosA)/cosA(1+2cosA)
= TanA
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