prove that sin square A + cos square A is equal to 1
kritinmishra12357:
Sin A=perpendicular/hypotenuse
Sin A=p/h; cos A =base(b)/hypotenuse (h).
Sin square A=p ^2/h^2
Here ^ denotes power is used
Cos square A=b^2/h^2
Sin ^2 A+cos^2 A= p^2+b^2/h^2
And p^2+b^2 =h^2
By Pythagoras theorem
So, sin ^2A+cos^2 A=h^2/h^2
Sin ^2 A+cos ^2 A=1
Answers
Answered by
44
Let A=90 for first condition
Sin2(90)+cos2(90)
1+0
1
Let A=0 for 2nd condition
Sin2(0)+cos2(0)
0+1
1
Hence proved
Hope this helps you
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Sin2(90)+cos2(90)
1+0
1
Let A=0 for 2nd condition
Sin2(0)+cos2(0)
0+1
1
Hence proved
Hope this helps you
Mark as a brainliest
can u do easy method
Answered by
3
Answer:
It has been proved that sin square A + cos square A is equal to 1
Step-by-step explanation:
We know that:
1 - cot² A = cosec² A
Multiplying by sin²A on both the sides, we get that:
(1 - cot²A) × sin²A = cosec²A × sin²A
sin²A - cot²A × sin²A = cosec²A × sin²A
Since cosec x = 1/sin x, we get that:
sin²A - cot²A × sin²A = 1
Since cot x can be written as cos x / sin x, we get that:
sin²A - (cos²A / sin²A) × sin²A = 1
Simplifying it, we get that:
sin²A+ cos²=1
Therefore, it has been proved that sin square A + cos square A is equal to 1
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