Question

prove that sin square A + sin square b *cos 2A= 2 sin square b + sin square A *cos B​

Answer 1

Answer:

LHS=(sinAcosB)

2

−(cosAsinB)

2

=(sinAcosB+cosAsinB)(sinAcosB−cosAsinB)

=sin(A+B)sin(A−B)

=sin

2

A−sin

2

B

=RHS

Hence proved