Prove that sin theta ÷ cos theta + coz theta = sec theta
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+ =
+/cosx
sinx + 1-sinx over cos x
(sinx/ cos) +(1/cosx) -sinx/cos x
tanx +1/cosx - tanx
1/cos=secx
LHS =RHS
+/cosx
sinx + 1-sinx over cos x
(sinx/ cos) +(1/cosx) -sinx/cos x
tanx +1/cosx - tanx
1/cos=secx
LHS =RHS
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