Prove that
sin thrita /sin (90-thrita)+cos thrita /cos(90-thrita)= sec thrita *cosec thrita.
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Yes it's correct
Step-by-step explanation:sin (90- theta)=cos theta
Cos (90- theta)=sin theta
sin thrita /sin (90-thrita)+cos thrita /cos(90-thrita)= sec thrita *cosec thrita.
By taking lhs,
=Sin theta/Cos theta+Cos theta /sin theta
=Sin^2 theta+cos^2/sin theta ×Cos theta (since sin^2a+cos^2a=1)
=1/Sin theta ×Cos theta ( since 1/sina=coseca ,1/cosa=seca)
=cosec theta×sec theta
There fore Hence proved
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