prove that sin to the power 6 thita +cos to the power 6 thita= 1-3sin to the power 2 cos to the power 2thita
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Step-by-step explanation:
Sin 6 theta + cos 6 theta =(sin2theta)3+(cos2theta)3
=(sin2theta +cos2theta)(sin4theta+cos4theta-sin2theta)
=(sin 2 theta + cos2theta)ka whole square-3sin2thetacos2theta
=1-3sin2thetacos2theta
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