Question

Prove that Sin²π/8+sin²3π/8=1

Answer 1

Step-by-step explanation:

$sin^{2}(pi \div 8) + sin^{2}(3\pi \div 8) \\ \sin^{2}(\pi \div 8 \: + \: 3\pi \div 8) \\ sin^{2} (pi \div 2) \\ (sin90)^{2} = (1)^{2} = 1$