Prove that: sin²θ / cos θ + cos θ = 1 / cos θ
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SOLUTION :
Given :
Sin²θ/cosθ+cosθ=secθ
L.H.S
(Sin²θ/cosθ)+cosθ
=( sin²θ + cos²θ)/cosθ
= 1 /cosθ
[By using trignometry identity ,sin²θ + cos²θ = 1]
= secθ [1 /cosθ = sec θ]
L.H.S = R.H.S
Hence, proved...
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