prove that sin2+cos2=1
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Answer:
LHS = sin^2a +cos^2a
sina =p/h
cos a = b/h
so sin^2a =p^2/h^2
and cos ^2a = b^2/ h^2
therefore sin^2a + cos^2a = p^2/h^2 +b^2/h^2
= p^2 +b^2 / h^2 eq 1
using Pythagoras theorem
i.e. perpendicular^2+base^2 = hypotenuse^2
p^2+ b^2 =h^2
using in eq 1
p^2+b^2 / h^2 = h^2/h^2 = 1
LHS = RHS
hence proved
please mark BRAINIEST
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