prove that sin²48°+sin²42° = 1
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sin and cos are complementary ratios
=> sinθ = cos(90°-θ)
sin²48° + sin²42° = sin²48° + cos²(90-42)°
= sin²48° + cos²48°
= 1 = R.H.S [sin²θ + cos²θ = 1]
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