prove that sin2A = 2sinAcosA
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Answered by
3
sin(2A) = sin(A + A)
As sin(a + b) = sinacosb + sinbcosa,
sin(A + A) = sinAcosA + sinAcosA
Therefore sin(2A) = 2sinAcosA
As sin(a + b) = sinacosb + sinbcosa,
sin(A + A) = sinAcosA + sinAcosA
Therefore sin(2A) = 2sinAcosA
Answered by
2
Step-by-step explanation:
sin2A=2sinAcosA
sin2A=sin(A+A)
sin(a+b)=sina cosb+sinb cosa
sin2A=2sinAcosA
Hence proved
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