Question

Prove that sin2A=2tanA/1+tanA.tanA​

Answer 1

Step-by-step explanation:

$\sf We\:know\:that$

$\sf sin2A = 2sinAcosA$

$\sf Multiplying \: numerator \: and \: denominator \: by \: {cos}^{2}A$

$\sf \frac { 2sinAcosA{cos}^{2}A}{{cos}^{2}A}$

$\sf \frac {2tanA}{{sec}^{2}A}$

$\sf \frac {2tanA}{1+{tan}^{2}A}$

THANKS!!!

Answer 2

Answer:

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