Prove that:
sin2A/cos2A+1= tan2A/sin2A
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Answer:
sin2A/cos2A+1=tan2A/sin2A
=>sin2A/sin2A -1+1=sin2A/cos2A/sin2A
=>sin2A/sin2A =sin2A/ cos2A×1/sin2A
=>1=1/cos2A
=>1=sec2A
My bad if it wrong
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