prove that sin²A/cos²A + cos²A/sin²A= 1/sin²A cos²A -2
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here is the ans
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tan⁴a-tan²a=1
tan⁴a-tan²a can be also written as
sin⁴a-sin²a/cos⁴a-cos²a
1/( cos²a)²-cos²
1/(1-sin²a)²-(1-sin²a)
now using identity (a+b)² as a² +b²+2ab
we get
1/sin⁴a-sin²a
1/1= 1
LHS=RHS
hence proved
THANKS
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