sin thetha = -2√6÷5, lies in fourth quadrant.
Find other trigonometric function
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there should not be divided either it is + or - sign
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Given sin theta= -2_/6/5
So, cosec theta= 5/-2_/6 or -10_/6/24 (rationalisation)
Now,
Sin^2theta + cos^2theta = 1
(-2_/6/5)^2 + cos^2 theta = 1
24/25 + cos^2 theta = 1
Cos^2 theta = 1 - 24/25
= 25-24/25
= 1/25
Cos theta = _/1/5
So, sec theta= 5/_/1 or 5_/1 (rationalisation)
Now,tan theta = sin theta / cos theta
= -2_/6/5 / _/1/5
= -2_/6 / _/1 or -2_/6 (rationalisation)
So, cot theta = -1/-2_/6
As theta lies in 4th quadrant so the value of cos and sec will be positive
So, cosec theta= 5/-2_/6 or -10_/6/24 (rationalisation)
Now,
Sin^2theta + cos^2theta = 1
(-2_/6/5)^2 + cos^2 theta = 1
24/25 + cos^2 theta = 1
Cos^2 theta = 1 - 24/25
= 25-24/25
= 1/25
Cos theta = _/1/5
So, sec theta= 5/_/1 or 5_/1 (rationalisation)
Now,tan theta = sin theta / cos theta
= -2_/6/5 / _/1/5
= -2_/6 / _/1 or -2_/6 (rationalisation)
So, cot theta = -1/-2_/6
As theta lies in 4th quadrant so the value of cos and sec will be positive
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