Question

Prove that, Sin2A + sin2B -sin2C =4cosA cosB cosC.​

Answer 1

Answer:

cosB+sinB.cosA =sinA(1+cosB)+sinB(1+cosA) = 2sinA/2. ... cosA/2) = 4.cosA/2.cosB/2(sin(A/2 +B/2)) = 4 cosA/2.cosB/2.cosC/2 . Proved.

1 vote

Answer 2

Answer:

ye answer aapko kaha se Mila please batao

or ye pakka sahi h na