Math, asked by srinidhiuppuluri853, 6 months ago

prove that sin2a tan a +cos2a cota+ 2sina cosa = tana +cota​

Answers

Answered by sahibsaifi12291
2

Step-by-step explanation:

L.H.S.= sin^2a * tana+ cos^2a* cota+ 2sina cosa

= sin^3a/cosa + cos^3a/sina + 2sina cosa

= [sin^4 + cos^4+ 2 sin^2a cos^2a]/sina cosa

= [sin^2a + cos^2a)^2/sina cosa

= 1/sina cosa

= [sin^a + cos^2a]/sina cosa [ because 1= sin^2 +cos^2a]

= sin^2a/sina cosa + cos^2a/sina cosa

= tan a+ cot a

= R.H.S.

1

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