Math, asked by bgarg582, 6 months ago

prove that sin3x + cos3x = √2 sin6x​

Answers

Answered by rajakr5343
0

Answer:

2sin6x

Step-by-step explanation:

LHS=sin3x+cos3x

=sin3x+cos(90°-3x)

=sin3x+sin3

= 2sin6x Ans

Similar questions