prove that sin45 = 1/√2
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The angle bisector is exactly the line of points equidistant from the two lines it bisects. The distance of C to AB is BC and the distance of C to AD is CD. Since ABCD is a square, BC=CD and thus C lies on the angle bisector. Now since the angle bisector also goes through A, it must be exactly the line AC.
Concerning other proofs, here's another, albeit similar, proof: It is clear from the same construction that sin45∘=cos45∘. Now since
(sinθ)2+(cosθ)2=1
we get:
2(sin45∘)2=1⇒sin45∘=1/√2
observing that it must be positive.
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