Question

prove that sin4theta - cos2theta =1-2 cos2theta​

Answer 1

Answer:

your answer is

Step-by-step explanation:

sin4 A take common sin2

sin4 A take common sin2 Prove

sin4 A take common sin2 Provesin2(θ)+cos4(θ)=cos2(θ)+sin4(θ)

sin4 A take common sin2 Provesin2(θ)+cos4(θ)=cos2(θ)+sin4(θ)I only know how to solve using factoring and the basic trig identities, I do not know reduction or anything of the sort, please prove using the basic trigonometric identities and factoring.

sin4 A take common sin2 Provesin2(θ)+cos4(θ)=cos2(θ)+sin4(θ)I only know how to solve using factoring and the basic trig identities, I do not know reduction or anything of the sort, please prove using the basic trigonometric identities and factoring.After some help I found that you move the identity around, so:

sin4 A take common sin2 Provesin2(θ)+cos4(θ)=cos2(θ)+sin4(θ)I only know how to solve using factoring and the basic trig identities, I do not know reduction or anything of the sort, please prove using the basic trigonometric identities and factoring.After some help I found that you move the identity around, so:sin2(θ)−cos2(θ)=sin4(θ)−cos4(θ)

sin4 A take common sin2 Provesin2(θ)+cos4(θ)=cos2(θ)+sin4(θ)I only know how to solve using factoring and the basic trig identities, I do not know reduction or anything of the sort, please prove using the basic trigonometric identities and factoring.After some help I found that you move the identity around, so:sin2(θ)−cos2(θ)=sin4(θ)−cos4(θ)Then,

sin4 A take common sin2 Provesin2(θ)+cos4(θ)=cos2(θ)+sin4(θ)I only know how to solve using factoring and the basic trig identities, I do not know reduction or anything of the sort, please prove using the basic trigonometric identities and factoring.After some help I found that you move the identity around, so:sin2(θ)−cos2(θ)=sin4(θ)−cos4(θ)Then,sin2(θ)−cos2(θ)=(sin2(θ)+cos2(θ))(sin2(θ)−cos2(