Prove that SinA÷1+CosA=1-SinA-CosA÷SinA-1-CosA
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LHS=[sinA1−cosA−1−cosA sinA][cosA1+sinA+1+sinAcosA]. Now 1st part = sinA1−cosA−1−cosAsinA. =sinA(1+cosA)(1 −cosA)(1+cosA)−1−cosAsinA.
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