Prove that :
sinA (1 + tanA) + cosA (1 + cotA) = secA + cosecA
Answer with complete steps.
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Answered by
7
hope it works for you
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Similar questions
=sinA(1+(sinA/cosA)) + cosA(1+(cosA/sinA))
=(sinA/cosA)(cosA+sinA) + (cosA/sinA)(sinA+cosA)
=(cosA+sinA)[(((SinA)^2+(cosA)^2)/sinA...
=(cosA+sinA)(1/sinAcosA)
=secA + cosecA
=rhs
hence proved