Prove that sina^2 +cosb^2=1
Answers
Answered by
1
★ Ello ★
here is your answer !!
sinA = perpendicular / hypotenuse
p / h
so , sina² = p² / h² -------------(1)
now ,
COSb = base / hypotenuse
Cosb² = b² / h² -------------------(2)
according to Pythagoras theroum
h² = p² + b²
on adding equation 1 and 2 we get
sina² + Cosb² => p² / h² + b² / h²
but {. p² + b² = h² }
=> h² / h²
=> 1
hence , proved
hope it helps you dear !!
here is your answer !!
sinA = perpendicular / hypotenuse
p / h
so , sina² = p² / h² -------------(1)
now ,
COSb = base / hypotenuse
Cosb² = b² / h² -------------------(2)
according to Pythagoras theroum
h² = p² + b²
on adding equation 1 and 2 we get
sina² + Cosb² => p² / h² + b² / h²
but {. p² + b² = h² }
=> h² / h²
=> 1
hence , proved
hope it helps you dear !!
Similar questions