Prove that : sinA - 2sin3A / 2cos3A - cosA = tanA
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Step-by-step explanation:
good question of trigonometric identity
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Step-by-step explanation:
sinA-2sin^3A/2cos^A-cosA=tanA
sol.from L.H.S
sinA(1-2sin^2A)/cosA(cos^2A-1)
=sinA(1-2sin^2)/cosA(2(1-sin^2)-1)
=sinA(1-sin^2A)/cosA(2-2sin^2A-1)
=sinA(1-sin^2A)/cosA(1-sin^2A)
=sinA/cosA
=tanA
hence proved
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