Math, asked by Karan9311, 1 year ago

Prove That

SinA - CosA +1 / SinA + CosA - 1 = 1/SecA - TanA

Answers

Answered by Dharmendr
3
LHS = (sinA-cosA+1)/(sinA+cos-1) = (1 + sinA) (1 - sinA)/cos A(1 - sinA) = 1 - sin2A/cos A(1 - sinA) = cos2A/cos A(1 - sinA) = cosA/(1 - sinA) = 1/ (1/cosA - sinA/cosA) = 1/(secA - tanA) = RHS Hence Proved
Dharmendr: welcome
Karan9311: Explain the second step
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