Question

Prove that sinA−cosA+1sinA+cosA−1=1secA−tanA

Answer 1

Answer:

LHS =

sin e - cos e + 1

= tan a 1 + sec e sin 8 + cos - 1 tan a + 1 - sec e

(tan e • sec ) - 1 (tan 8 + sec e) - 1 (tan e - sec )

(tan - sec ) + 1 {(tan 8 - sec e) + 1 (tan 8 - sec ) (tan? e - sec - (tan e - sec )

tan 8 - sec 1 (tan 8 - sec )

-1

tan a - sec e

= 1 sec x tan 8

: tan 8- sec e-

Answer 2

Answer:

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