prove that sinA+cosA=√2 cos(45°-A)
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Hiii
Required answer...
Multiplying and divide LHS √2
√2 (1/√2 sin A + 1/√2 cos A)
and sin 45 = cos 45 = 1/√2
=> √2 ( sin 45 sin A + cos 45 cos A)
=> √2 cos(45-A )
Hope it helps.
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