prove that :sinA+cosA>1
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Step-by-step explanation:
for right angle triangle
sinA=p/h
cos A=b/h
We know that for any triangle sum of any two sides is greater than the third.
so, taking
LHS=sinA+cosA=p/h+b/h
=(p+b)/h
>1. (p+b>h)
reference-
p-perpendicular, b- base and
h-hypotenuse.
proved.
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