Math, asked by basit75, 11 months ago

prove that :sinA+cosA>1​

Answers

Answered by sibi61
1

Hi buddy

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Answered by anil531
1

Step-by-step explanation:

for right angle triangle

sinA=p/h

cos A=b/h

We know that for any triangle sum of any two sides is greater than the third.

so, taking

LHS=sinA+cosA=p/h+b/h

=(p+b)/h

>1. (p+b>h)

reference-

p-perpendicular, b- base and

h-hypotenuse.

proved.

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