Question

prove that (sinA+cosecA)^2+(cosA+secA)^2=7+tan^2​

Answer 1

Answer:

Hope you will understand well from video and happy with my resume

Answer 2

Answer:

Step-by-step explanation:

=(sinA+cosecA)²+(cosA+secA)²

=sin²A+cosec²A+2sinAcosecA+cos²A+sec²A+2cosAsecA

=sin²A+cos²A+cosec²A+sec²A+2sinA×1/sinA+2cosA×1/cosA

=1+cosec²A+sec²A+2+2

=5+(1+cot²A)+(1+tan²A)

=7-tan²A-cot²A

Identities used:

tan²A+1=sec²A

1+cot²A=cosec²A

sin²A+cos²A=1

cosecA=1/sinA

secA=1/cosA

Mark My Answer As The Brainliest