prove that sinA.secA=tanA
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Answered by
2
secA=1/cosA
Now sinA.secA=sinA/cosA=tanA
Now sinA.secA=sinA/cosA=tanA
Answered by
2
sinA=sinA
secA=1/cosA
so
sinA.secA=sinA.1/cosA= sinA/cosA= tanA
secA=1/cosA
so
sinA.secA=sinA.1/cosA= sinA/cosA= tanA
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