prove that sina+ sin3a + sin5a + sin7a ÷ cosa + cos3a + cos5A+cos7a =tan4a
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write the numerator as
(sin3a + sin5a) + (sina+sin7a)
= 2sin4acos3a + 2sin4acosa
=2sin4a( cos3a + cosa)
Similarly for denominator u get,
= 2cos4a(cos3a+cosa)
hence u get tan4a
(sin3a + sin5a) + (sina+sin7a)
= 2sin4acos3a + 2sin4acosa
=2sin4a( cos3a + cosa)
Similarly for denominator u get,
= 2cos4a(cos3a+cosa)
hence u get tan4a
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