prove that sinAcosA=1/tanA+cotA
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Step-by-step explanation:1/tanA+cotA
=1/ sinA/cosA + cosA/sinA
=1/ sin^2A+cos^2A /sinAcosA
=1 x sinAcosA/ sin^2A+cos^2A
=sinAcosA=RHS
Hence peoved
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