prove that sinx/2 sin7x/2 + sin3x/2 sin11x/2 = sin2xsin5x
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use formula 2sinA.sinB =cos (A-B)-cos (A+B)
hence 1/2 (cos3x-cos4x)+1/2 (cos4x-cos7x)=1/2 (cos3x-cos7x)
=1/2 (2sin5x. sin2x)
=sin5x. sin2x
hence 1/2 (cos3x-cos4x)+1/2 (cos4x-cos7x)=1/2 (cos3x-cos7x)
=1/2 (2sin5x. sin2x)
=sin5x. sin2x
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