Question

Prove that Snth=u+a/2(2n-1)​

Answer 1

a.. acceleration

distance covered in n sec=un+1/2an^2

distance covered in( n-1)sec=

u (n-1)+1/2a(n-1)²=un-u + 1/2a(n^2-2n+1)

now distance in nth(snth)=

dist. covered in nth - dist.in n-1

ie.

un+1/2an^2-un+n-1/2an^2+1/2.2n-1/2

=u+a/2(2n-1)

ans...