Question

prove that square of any old positive integer of the form 6m+1 or 6m+3 where m is some integer​

Answer 1

Answer:

Step-by-step explanation:

Let n be a given positive odd integer.

On dividing n by 6 , let m be the Quotient and r be the remainder.

Then, by Euclid division lemma, we have

Dividend = Divisor × Quotient + Remainder

n = 6m + r. where r = 0 , 1 ,2 , 3 ,4 ,5

n= 6m + 0 = 6m. [ r =0]

n = 6m + 1 = 6m+1 [ r = 1 ]

n = 6m +2 = 6m +2 [ r = 2 ]

n = 6m +3 = 6m+3 [ r = 3 ]

n = 6m +4 = 6m+4 [ r = 4 ]

n = 6m+5 = 6m+5 [ r = 5 ]

N = 6m , (6m +2) , (6m+4) is even value of n.

Therefore,

when n is odd , it is in the form of (6m+1) , (6m+3) ,  for some integer m.