Question

Prove that... statistical equations urgent please!!

Answer 1

Answer:

$\Sigma(x_i-\bar{x})=0$

Step-by-step explanation:

Formula used:

$Mean,\:\bar{x}=\frac{\Sigma{x}}{n}$

I have proved that

$\Sigma(x_i-\bar{x})=0$

Now,

$\Sigma(x_i-\bar{x})$

$=\Sigma{x_i}-\Sigma{\bar{x}}$

$=(x_1+x_2+x_3+.......+x_n)-(\bar{x}+\bar{x}+\bar{x}........n\:times)$

$=n\bar{x}-n\bar{x}$

$=0$