Vikram borrowed 20000 from a bank at 10% per annum simple interest. he lent it to his friend Venkat @ same rate but compared annually. Find his gain after two and a half years
Answers
Answer:
Step-by-step explanation:
Principle amount(P) = 20000;
Rate of interest(R) = 10%;
Time(T) = 2.5 Years
Simple interest = PRT/100;
= 20000*10*2.5/100 = 5000;
Compound Interest = P{1 + R/100}^T;
Here rate of interest count as half yearly;
So R = R/2 and T = 5;
= 20000[1 + 10/2*100]^5;
= 20000[1.05]^5;
= 20000*1.27 = 25525.6
Gain = Compound Interest - Simple Interest;
Gain = 25525.6-5000 = 20525.6
Answer:
Rs 380
Rs 410
Step-by-step explanation:
Simple interest = P * R * n/100
P = Principle = Rs 20000
R = 10% per annum
n = 2.5 Years
Simple interest for 2.5 Years = 20000 * 10 * (2.5)/100 = Rs 5000
Compound interest = P ( 1 + r/100)ⁿ - P
Gain = Compound interest - Simple Interest
=> Gain = 5380 - 5000
=> Gain = Rs 380
This is based on formula of compound interest
as this formula start compounding for a smaller period than compounding period but in actual compounding is done at per mentioned period only
But if we do it other way
Simple interest & Compound interest for 1st year = Equal
= 20000 * 10 * 1/100 = Rs 2000
in Second year
Simple interest = Rs 2000 again
now compound interest will be calculated on interest gained also
but compound interest = (20000 + 2000) * 10 * 1/100 = Rs 2200
Additional Compound interest = Rs 200
in 3rd year for 6 months = (0.5 Years)
Simple interest = 20000 * 10 * 0.5/1000 = 1000
Compound interest = (20000 + 2000 + 2200) * 10 * 0.5/100
= 1210
Extra interest in 6 months for 3 rd year = 1210 - 1000 = Rs 210
Total extra interest = Rs 200 + 210 = 410
Gain = Rs 410