Question

prove that Su(SnT)=Sn(SuT)=S

Answer 1

Answer:

y=log(logx)

Again differentiate both sides w.r.t. x

dx

dy

=

logx

1

dx

d

(logx)

dx

dy

=

logx

1

×

x

1

×1

dx

dy

=

xlogx

1

Again differentiate both sides w.r.t. x

dx

2

d

2

y

=

(xlogx)

2

xlogx(0)−1[logx+x×

x

1

]

dx

2

d

2

y

=

(xlogx)

2

−(1+logx)