Prove that Su(SnT)=Sn(SuT)=S
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Answer:
Step-by-step explanation:
y=log(logx)
Again differentiate both sides w.r.t. x
dx
dy
=
logx
1
dx
d
(logx)
dx
dy
=
logx
1
×
x
1
×1
dx
dy
=
xlogx
1
Again differentiate both sides w.r.t. x
dx
2
d
2
y
=
(xlogx)
2
xlogx(0)−1[logx+x×
x
1
]
dx
2
d
2
y
=
(xlogx)
2
−(1+logx)
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