prove that sum of the three angles of a triangle is 180°
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Refer the attachment for figure.
Construct a triangle ABC and name the :-
angle A = x,
angle B = y
angle c = z
Now construct a line parallel to BC crossing A. Name. the line as ED (refer the attachment)
Now you will find that,
Angle DAB = y (alternate angle)
and, angle EAC = z (alternate angle)
and, angle DAB, angle A, angle EAC lies on a line ED.
We know that the sum of angles lying on a line is 180°
=> angle DAB + angle A + angle EAC = 180°
but, angle DAB = y, angle A = x and angle EAC = z
=> x + y + z = 180°
And x, y and z are the angles of a triangle
=> sum of angles of a triangle = 180°
Hence Proved :)
Construct a triangle ABC and name the :-
angle A = x,
angle B = y
angle c = z
Now construct a line parallel to BC crossing A. Name. the line as ED (refer the attachment)
Now you will find that,
Angle DAB = y (alternate angle)
and, angle EAC = z (alternate angle)
and, angle DAB, angle A, angle EAC lies on a line ED.
We know that the sum of angles lying on a line is 180°
=> angle DAB + angle A + angle EAC = 180°
but, angle DAB = y, angle A = x and angle EAC = z
=> x + y + z = 180°
And x, y and z are the angles of a triangle
=> sum of angles of a triangle = 180°
Hence Proved :)
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