prove that sum of three angles of a triangle is 180°
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Draw line a through points A and B. Draw line b through point C and parallel to line a.
Since lines a and b are parallel, <BAC = <B'CA and <ABC = <BCA'.
It is obvious that <B'CA + <ACB + <BCA' = 180 degrees.
Thus <ABC + <BCA + <CAB = 180 degrees.
Since lines a and b are parallel, <BAC = <B'CA and <ABC = <BCA'.
It is obvious that <B'CA + <ACB + <BCA' = 180 degrees.
Thus <ABC + <BCA + <CAB = 180 degrees.
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