PROVE THAT :
[tan Ф ÷ 1 - cot Ф] + [cot Ф ÷ 1 - tan Ф] = 1 + sec Ф × cosec Ф
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Inverse of a function 'f ' exists, if the function is one-one and onto, i.e, bijective. ... x ∈[–1,1] tan (tan–1 x) = x. : x ∈R cot (cot–1 x) = x. : x ∈R sec (sec–1 x) = x ... If 2 tan –1 (cos θ) = tan–1 (2 cosec θ), then show that θ = π.
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