prove that tan 1*tan 89 + tan 2*tan 88 - tan 3*tan 87 - tan 4*tan 86 = 0
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Answer:
tan1 = cot(90-1) =cot 89
tan 2= cot 90-2= cot 88
tan 3= cot 90-3 = cot 87
tan4=cot 90-4 =cot86
so putting the value we get
cot 89 tan89 + cot 88 tan 88 - cot 87 tan 87 -
cot 86 tan 86
we know that tanx*cotx=1
so
1+1-1-1=2-2
0 hence proved
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