Prove that tan (180- theta) cosec(180+theta)-sin(90-theta) = tan theta sin theta
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tan(180-theta)cosec(180-theta)-sin(90-theta)
=tan(theta)(-cosec(theta))-cos(theta)
= -(sin(theta)/cos(theta))*(1/sin(theta)) -cos(theta)
= -(1/cos(theta)) -cos(theta)
= -(1-cos² theta )/cos theta
= -(-sin² theta)/cos theta
= sin² theta/cos theta
= tan theta sin theta
=tan(theta)(-cosec(theta))-cos(theta)
= -(sin(theta)/cos(theta))*(1/sin(theta)) -cos(theta)
= -(1/cos(theta)) -cos(theta)
= -(1-cos² theta )/cos theta
= -(-sin² theta)/cos theta
= sin² theta/cos theta
= tan theta sin theta
aayushjha48:
I hope it helps you
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