Math, asked by palbinod22, 1 year ago

Prove that tan^2A-tan^2B=(sin^2A-sin^2B)/(cos^2B-cos^2A)

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Answered by Anonymous
3
I hope this will help u...
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palbinod22: See the question carefully. RHS is (sin^2A-sin^2B)/(cos^2B-cos^2A).
Anonymous: Okk I will correct it now ..
Anonymous: Are u sure that there is minus sign in the denominator
Anonymous: I have done correctly.. might be u have copied wrongly , there will be no minus sign in the denominator
palbinod22: u are right. thanks
Anonymous: plz mark it as brainliest
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