Prove that tan 315°×cot(-405°) +cos 495°×tan(-585°) =2
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Prove that tan 315°×cot(-405°) +cos 495°×tan(-585°) =2
ANSWER
We have
Tan 315 = tan(360 – 45) = - tan 45 = - 1
Cot (- 405) = - cot 405 = - cot(360 + 45) = cot 45 = - 1
Cot 495 = cot(360 + 135) = cot 135 = cot(180 – 45) = - cot 45 = -1
Tan ( 585) = - tan 585 = tan(360 + 225) = - tan 225 = - tan(180 + 45) = - tan 45 = -1
Tan 315 x cot 405 + cot 495 x tan – 585
-1 x – 1 + - 1 x -1
= 2
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