prove that: tan 3A - tan 2A - tanA = tan 3A tan 2A tan A.
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Answer:
3A - tan 2A - tanA = tan 3A tan 2A tan A proved.
Step-by-step explanation:
3A - tan 2A - tanA = tan 3A tan 2A tan A.
So, we can write the right hand side as tan3A = tan(2A+A), which is having a formulae of tan3A=(tan2A+tanA)/(1-tan2AtanA) this can again be written as tan3A(1-tan2AtanA)=(tan2A+tanA).
So, now tan3A - tan3A*tan2A*tanA = tan2A+tanA.
Hence, tan3A-tan2A-tanA= tan3A*tan2A*tanA. Therefore right hand side is same as left hand side from the question. So, it is proved.
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